Optimal. Leaf size=39 \[ -\frac{\log \left (a+b x^n\right )}{a^2 n}+\frac{\log (x)}{a^2}+\frac{1}{a n \left (a+b x^n\right )} \]
[Out]
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Rubi [A] time = 0.064068, antiderivative size = 39, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 13, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.154 \[ -\frac{\log \left (a+b x^n\right )}{a^2 n}+\frac{\log (x)}{a^2}+\frac{1}{a n \left (a+b x^n\right )} \]
Antiderivative was successfully verified.
[In] Int[1/(x*(a + b*x^n)^2),x]
[Out]
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Rubi in Sympy [A] time = 9.59624, size = 34, normalized size = 0.87 \[ \frac{1}{a n \left (a + b x^{n}\right )} + \frac{\log{\left (x^{n} \right )}}{a^{2} n} - \frac{\log{\left (a + b x^{n} \right )}}{a^{2} n} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/x/(a+b*x**n)**2,x)
[Out]
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Mathematica [A] time = 0.070419, size = 34, normalized size = 0.87 \[ \frac{\frac{a}{a n+b n x^n}-\frac{\log \left (a+b x^n\right )}{n}+\log (x)}{a^2} \]
Antiderivative was successfully verified.
[In] Integrate[1/(x*(a + b*x^n)^2),x]
[Out]
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Maple [A] time = 0., size = 45, normalized size = 1.2 \[{\frac{\ln \left ({x}^{n} \right ) }{{a}^{2}n}}-{\frac{\ln \left ( a+b{x}^{n} \right ) }{{a}^{2}n}}+{\frac{1}{an \left ( a+b{x}^{n} \right ) }} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/x/(a+b*x^n)^2,x)
[Out]
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Maxima [A] time = 1.43452, size = 58, normalized size = 1.49 \[ \frac{1}{a b n x^{n} + a^{2} n} - \frac{\log \left (b x^{n} + a\right )}{a^{2} n} + \frac{\log \left (x^{n}\right )}{a^{2} n} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b*x^n + a)^2*x),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.226626, size = 68, normalized size = 1.74 \[ \frac{b n x^{n} \log \left (x\right ) + a n \log \left (x\right ) -{\left (b x^{n} + a\right )} \log \left (b x^{n} + a\right ) + a}{a^{2} b n x^{n} + a^{3} n} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b*x^n + a)^2*x),x, algorithm="fricas")
[Out]
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Sympy [A] time = 3.65584, size = 160, normalized size = 4.1 \[ \begin{cases} \tilde{\infty } \log{\left (x \right )} & \text{for}\: a = 0 \wedge b = 0 \wedge n = 0 \\\frac{\log{\left (x \right )}}{a^{2}} & \text{for}\: b = 0 \\- \frac{x^{- 2 n}}{2 b^{2} n} & \text{for}\: a = 0 \\\tilde{\infty } \log{\left (x \right )} & \text{for}\: b = - a x^{- n} \\\frac{\log{\left (x \right )}}{\left (a + b\right )^{2}} & \text{for}\: n = 0 \\\frac{a n \log{\left (x \right )}}{a^{3} n + a^{2} b n x^{n}} - \frac{a \log{\left (\frac{a}{b} + x^{n} \right )}}{a^{3} n + a^{2} b n x^{n}} + \frac{a}{a^{3} n + a^{2} b n x^{n}} + \frac{b n x^{n} \log{\left (x \right )}}{a^{3} n + a^{2} b n x^{n}} - \frac{b x^{n} \log{\left (\frac{a}{b} + x^{n} \right )}}{a^{3} n + a^{2} b n x^{n}} & \text{otherwise} \end{cases} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/x/(a+b*x**n)**2,x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (b x^{n} + a\right )}^{2} x}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((b*x^n + a)^2*x),x, algorithm="giac")
[Out]